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E7D13
Which of the following calculates power dissipated by a series linear voltage regulator?
Pick an answer to check it.
Answer: C. Voltage difference from input to output multiplied by output current
A series regulator drops the extra voltage across its pass element while carrying the load current. P = (Vin - Vout) x Iout; for example (15 V - 12 V) x 2 A = 6 W.
Tip: Power lost = voltage drop x load current.